Web30 nov. 2012 · year%4==0&&year%100!=0 就是能被4整除的非整百年，是闰年。 year%400==0 就是能被400整除的整百年，是闰年。 year%100==0 && year%400!=0 就 … Web23 jun. 2013 · Teams. Q&A for work. Connect and share knowledge within a single location that is structured and easy to search. Learn more about Teams
if(year%4==0&&year%100!=0 year%400==0)如何理解？-慕课网
Web19 mrt. 2024 · def is_leap(year): return year % 4 == 0 and year % 100 != 0 or year % 400 == 0 Share. Improve this answer. Follow answered Aug 15, 2016 at 17:40. JBallin JBallin. 8,075 3 3 gold badges 42 42 silver badges 51 51 bronze badges. Add a comment 0 I used this short method: ... Web9 okt. 2016 · Closed. superbool opened this issue on Oct 9, 2016 · 1 comment. nathanielc closed this as completed on Oct 11, 2016. Sign up for free to join this conversation on … spicy spears ooblets
C语言一个小问题，这里的(year%100!=0)是什么意思呢_百度知道
Web16 mei 2024 · leap = ( (year % 4 == 0) && (year % 100 != 0)) (year % 400 == 0); 由于“=”赋值运算符优先级低且由右向左。 所以先看右边，也就是右边的式子的值赋值与leap。 右边有3个式子。 式子的值为真则1，假则0。 式子1：如果year被4整除则真，式子2：year不被100整除则真，式子3：year被400整除则真。 三者关系：（式子1&&式子2） 式子3 式 … Web4以下程序的功能是:判断从键盘输入的年份是否是闰年。 判断闰年的方法是:能被4整除但不能被100整除,或能被400整除,请填空完成该程序。 # include main( ) eg:200{int x, i;scanf ( % d ”, & x);if ( x % 400 = = 0 ) i=1;else if (__x%4==0&&x%100!=0__________________) i= 1;else ___i=0_______;if ( i= = 1) printf (“ This year is a leap year”);;if ( i= = 0) printf (“ This year … Web17 jul. 2024 · A very simple solution using the if-else statement function isLeap (year) { if (year % 4 === 0 year % 400 === 0) { console.log ("Leap Year"); } else if (year % 100 === 0) { console.log ("Not Leap Year"); } else { console.log ("Not Leap Year"); } } //and then call the function isLeap (2024); Share Improve this answer Follow spicy sparks esound